Posted by julie on Monday, November 26, 2007 at 11:21pm.
Well, dx= du/(2sec2x tan 2x) from your equation.
INT 2sec2x tan2x * dx= INT du
INT du= u
On the second.
You have u^30 du/3 since dx=du/3
INT u^30 du/3 = 1/3 INT u^30 du=
1/3 * 31 u^31
then on both, substitute back in the f(x) for u.
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