A 50 kg skater pushed by a friend accelerates 5 m/sec. How much force did the friend apply?

THANK YOU SM

F = m*a

You're given mass and acceleration. Just multiply them. Your answer will be in newtons (N).

To determine the force applied by the friend, we can use Newton's second law of motion which states that force (F) is equal to mass (m) multiplied by acceleration (a).

Given:
Mass of the skater (m) = 50 kg
Acceleration (a) = 5 m/s²

Using the formula:
F = m x a

Substituting the given values:
F = 50 kg x 5 m/s²

Calculating the force:
F = 250 Newtons

Therefore, the friend applied a force of 250 Newtons.

To figure out the force applied by the friend, we can use Newton's second law of motion, which states that force (F) equals mass (m) multiplied by acceleration (a):

F = m * a

In this case, the given mass of the skater is 50 kg, and the acceleration is 5 m/sec. Plugging in these values, we can calculate the force applied by the friend:

F = 50 kg * 5 m/sec
F = 250 Newtons

Therefore, the friend applied a force of 250 Newtons to accelerate the skater.