Posted by **Olivia** on Monday, November 26, 2007 at 12:14pm.

Consider yourself a genetic counselor. Megan and Eric come to you for your services. They are planning on having their first child. Megan’s father died from Huntington’s disease. Eric’s family has no history of Huntington’s disease. They would like to have the following questions answered before they undertake the awesome responsibility of parenthood.

1. What is the probability Megan will develop the symptoms of Huntington’s disease? (Assume her mother was hh.) Show the sample space.

2. What is the probability that their first child will develop Huntington’s disease?

*ive tried to work it out and talk to my professor will not help me, please help!!!!

- math -
**Ms. Sue**, Monday, November 26, 2007 at 12:18pm
Apparently you tried to copy and past the questions -- but it didn't work. Please type the questions.

Then post the answers that you think should be answered. We'll be glad to comment on your answers.

- math -
**Olivia**, Monday, November 26, 2007 at 12:32pm
1.What is the probability Megan will develop the symptoms of Huntington’s disease? (Assume her mother was hh.) Show the sample space.--50%

2.What is the probability that their first child will develop Huntington’s disease?--25% chance having disease, 75% chance doesnt have disease

3.If Megan and Eric have three children, what is the probability that at least one of them will have Huntington’s disease? Round to the nearest tenth of a percent.--each kid has same chance

4.If Megan and Eric have two children, what is the probability that at least one of the will have Huntington’s disease? Round to the nearest tenth of a percent.--each kid has same chance

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**Ms. Sue**, Monday, November 26, 2007 at 1:40pm
Your first two answers are correct. However, the 3rd and 4th questions ask what is the probability that one of their children will have the disease. You're right that each child has the same chance -- 1 of 4. But the more children this couple has, the more chances are that at least one child will have the disease.

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