Use the given information to find the exact value of the expression:
Find cos(2, q),csc q =
q lies in quadrant II
-7/25
24/25
7/25
-24/25
I'm confused by the notation.
You can't have cos(2,q). The cosine functions yields an angle given the adjacent and hypotenuse.
Can you please clarify your question?
Find cos(2,è),csc è = è lies in quadrant II
I didn't have a theta sign so I used q
-7/25
24/25
7/25
-24/25
You can just use x instead of theta.
cos(2x)csc(x)
Is this correct? We are multiplying cosine of 2 theta by cosecant of theta?
yes
They have to give you some number to solve this.
Are you sure it's not find cos(2x) given csc(x) = some number they give you?
exact question is :
Use the given information to find the exact value of the expression
Find cos(2,x),csc x= x lies in quadrant II
-7/25
24/25
7/25
-24/25
I still don't fully understand the notation and the commas. Sorry, maybe someone else can help you.
thanks anyway
To find the value of cos(2q), we'll need to know the value of cos(q).
Given that csc(q) = -7/25, we can determine sin(q) by taking the reciprocal: sin(q) = -25/7.
Since q lies in quadrant II (where sin is positive and cos is negative), we can determine cos(q) using the Pythagorean identity: cos^2(q) = 1 - sin^2(q).
Plugging in the values, we get cos^2(q) = 1 - (-25/7)^2 = 1 - 625/49 = -576/49.
Since cos(q) is negative, we take the negative square root: cos(q) = sqrt(-576/49).
Now, to find cos(2q), we'll use the double angle formula: cos(2q) = cos^2(q) - sin^2(q) = -576/49 - (-25/7)^2.
Plugging in the values, we get cos(2q) = -576/49 - 625/49 = -1201/49.
Therefore, the exact value of cos(2q) when q lies in quadrant II and csc(q) = -7/25 is -1201/49.