Posted by xxCeLoL on Monday, November 26, 2007 at 7:00am.
I got a few questions.
Hope ya'll can help out.
1) for F(X) = 6x  2x^2
Find the gradient of the chord joining the point where the X coorinates are 1 and (1+h) respectively.
b) hence find the gradient at x=1
2) Find the Coordinates of the point on the curve Y=1/2x^3  3/2x^2 +2x +1
at which the tangent:
a) is parallel to the X axis
b) makes an angle with the x axis whose tangent is 2
c) is parallel to y  6x  1 = 0
3) Find the equation of the tangent and normal to y= SQUAREROOT(x) at the point where X= 4
4) Find the equations of the tangents to
Y = 1/3x^3  x^2  x + 1
At the points where the tangent is parallel to Y  7x = 5
5) Find dy/dx for y^3  xy + 7 = 8
find the gradient when X = 0
I know this is quite a few questions.
I've missed out on so much from maths I don't understand A LOT of these questions. So any help in advance (even 1 question) will be MUCH appreciated!!!

Calculus  Maths  Michael, Monday, November 26, 2007 at 7:07am
5) You'll have to implicitly differentiate y with respect to x. That means differentiate x normally and apply the chain rule when you differentiate y. Don't forget the product rule with the x*y. I don't know about the gradient part.
4) Find y' by differentiating. Find your slope from y  7x = 5. (Parallel lines have equal slopes.)
3) Find the derivative. Evaluate the derivative at the given point, x=4. Solve for b (in y = mx+b).
2) Start by differentiating.
1) I don't know anything about gradients.
Work with those hints and see what you get. I can help you where you get stuck.

Calculus  Maths  xxCeLoL, Monday, November 26, 2007 at 7:14am
I just looked up the quotient, product and product rule.
I'm screwed i cant remember all those for my test.!

Calculus  Maths  Michael, Monday, November 26, 2007 at 7:33am
Yes, you can...
The product rule is "first, derivative of the second + second, derivative of the first."
The quotient rule is "bottom, derivative of the top minus top, derivative of the bottom all over the bottom squared."
(The commas are multiplication.) Say those statements in your head every time you differentiate using the quotient or product rule.

Calculus  Maths  xxCeLoL, Monday, November 26, 2007 at 7:50am
Can i please get an elaboration of the questions.

Calculus  Maths  bobpursley, Monday, November 26, 2007 at 7:59am
A gradient is the first derivative with respect to direcion, in this case, x.
Example: Temperature gradient.
dTemp/dx is the temperature gradient in the direction of x.
dTemp/dy is the termperature gradient in the direction of y.
Gradients are normally vectors.

Calculus  Maths  xxCeLoL, Monday, November 26, 2007 at 9:42pm
thanks
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