Thursday

August 28, 2014

August 28, 2014

Posted by **Ben !!!HELP!!!** on Sunday, November 25, 2007 at 9:29pm.

q=-p^2+33p+9 so

R=p(-p^2+33p+9) or =-p^3+33p^2+9p

I then need to take the derivative

R'=-3p^2+66p+9

Now I somehow need to solve for p to determine my price to obtain my largest revenue. How do I do this.

- Calc w/ Business -
**economyst**, Tuesday, November 27, 2007 at 9:00amTo find a maximum, set your marginal revenue (R') equal to zero. Now then, R' is a quadradic equation. So, use the quadradic formula.

-b +- sqrt(b^2+4ac) / 2a

- Calc w/ Business -
**economyst**, Tuesday, November 27, 2007 at 9:12ammy bad. it's -4ac in the quadradic, not +4ac

**Related Questions**

Calc - Demand is q=-p^2+33p+9 copies of a book sold per week when price is p ...

Calc - Profit=p(-p^2+33p+9)-9(-p^2+33p+9)+100 How do I simplify this so I can ...

Calc - Profit=p(-p^2+33p+9)-9(-p^2+33p+9)+100 How do I simplify this so I can ...

Calculus - with the equation q=-p^2+33p+9 (18 less than or equal to p less than ...

Calculus - ohaganbooks is offering a wide range of online books, including ...

Algebra - You operate a gaming Web site, where users must pay a small fee to log...

math - You operate a gaming Web site, where users must pay a small fee to log on...

Calc - a fast food place sells 425 large orders of fries per week at price $2....

Economics - Suppose a manager is interested in implementing third-degree price ...

college/microeconomics - Just needing to know if I have done the work correctly ...