Posted by **Ben !!!HELP!!!** on Sunday, November 25, 2007 at 9:29pm.

I have to determine the price that needs to be charged to obtain the largest revenue.

q=-p^2+33p+9 so

R=p(-p^2+33p+9) or =-p^3+33p^2+9p

I then need to take the derivative

R'=-3p^2+66p+9

Now I somehow need to solve for p to determine my price to obtain my largest revenue. How do I do this.

- Calc w/ Business -
**economyst**, Tuesday, November 27, 2007 at 9:00am
To find a maximum, set your marginal revenue (R') equal to zero. Now then, R' is a quadradic equation. So, use the quadradic formula.

-b +- sqrt(b^2+4ac) / 2a

- Calc w/ Business -
**economyst**, Tuesday, November 27, 2007 at 9:12am
my bad. it's -4ac in the quadradic, not +4ac

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