Posted by ANYONE Smart on Sunday, November 25, 2007 at 8:20pm.
Set up a system of equations to model the situation.
Let a be the number of adult tickets sold, and let c be the number of child tickets sold.
See what you get, and I'll help you.
a+c=20??
That's one of your equations, but a system of equations is two equations.
Find the other using the ticket pricing.
13a+3c=200??
Yes, very good. Now, we are trying to find the number of children who attended the play (c).
We have these equations:
a + c = 20
13a + 3c = 200
The easiest way to solve this is substitution. Solve the first equation for a, and then plug that into the second equation. You will then have all c's in the equation and will be able to solve it like any other equation.
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