Still need help please:

Stan invested $13,000, part at 17% and part at 2%. If the total interest at the end of the year is $1,910, how much did he invest at 17%?

Still need help please:

Stan invested $13,000, part at 17% and part at 2%. If the total interest at the end of the year is $1,910, how much did he invest at 17%?

Let x = the 17% quantity and y = the 2% quantity. Then
.17x + .02y = 1910
Also, x + y = 13,000

I bet you can take it from here.

still having some trouble

To find out how much Stan invested at 17%, we can set up an equation based on the given information.

Let's say Stan invested x dollars at 17%. Since the total amount he invested is $13,000, the amount he invested at 2% will be (13,000 - x) dollars.

The interest earned on $x at 17% would be (x * 0.17), and the interest earned on ($13,000 - x) at 2% would be ((13,000 - x) * 0.02).

According to the given information, the sum of these two interests should be $1,910. So we can write the equation:

(x * 0.17) + ((13,000 - x) * 0.02) = 1,910

To solve this equation, we can start by distributing the multiplication:

0.17x + 0.02(13,000) - 0.02x = 1,910

0.17x + 260 - 0.02x = 1,910

Now, let's combine the x terms and the constant terms:

0.15x + 260 = 1,910

Subtract 260 from both sides of the equation:

0.15x = 1,910 - 260

0.15x = 1,650

Divide both sides of the equation by 0.15:

x = 1,650 / 0.15

x = 11,000

Therefore, Stan invested $11,000 at 17%.