Thursday

February 11, 2016
Posted by **Ben** on Sunday, November 25, 2007 at 1:46pm.

I solved this as a Max Revenue problem and got x=0 and x=22 so the books should be sold for $22 each. IS THIS RIGHT?

Also, cost is C=9q+100 dollars to sell q copies of a book in a week. What price should the company charge to get the largest weekly profit? What is the max possible profit weekly profit and how can you be certain that the profit is maximized?

I got the profit function to be P=p(-p^2+33p+9)-9(-p^2+33p+9)+100. I simplified this to P=(-p^2+33+9)(p-9+100). I then took the derivative using the product rule to get P'=-2p+33(p-9+100)+(1)(-p^2+33p+9). I know I then need to set this equal to zero if it is right, I then have to factor and say which value maximizes profit. IS THIS RIGHT? Please help me to solve this part, I do not know how to solve P' equal to zero and factor

- Calc -
**bobpursley**, Sunday, November 25, 2007 at 2:22pmlargest revenue is q*p

revenue=qp

dR/dq=d/dq (-p^3 + 33p^2 + 9p)=0

solve that equation.

I get (22+-22.3)/2= 22

Now, cost.

Profit= revenue-cost

Profit= qp -9q+100

dP/dp= p(dq/dP) + q -9 dq/dp

where dq/dP=(-2p+33) and q=-p^2+33p+9

setting to zero

0=-2p^2+33p-p^2+33p+9-9(-2p+33)

0=-3p^2+48p-33*9

check that, then use the quadratic equation to solve it.

- Calc -
**bobpursley**, Sunday, November 25, 2007 at 2:23pmI see I made at least one error, in the constant. Check it line by line.

- Calc -
**Ben**, Sunday, November 25, 2007 at 2:30pmFor the first part I took R' and set this equal to zero to get 22, is this right too.

- Calc -
**Ben**, Sunday, November 25, 2007 at 2:32pmI am confused on how you did the cost part. I think I got P' but I don't see this in your work. I know I have to set P' equal to zero but I don't know if I have to factor or something first

- Calc -

- Calc -
- Calc -
**bobpursley**, Sunday, November 25, 2007 at 2:50pmYes, p=22 for max R.

On the second, profit, just start with revenue-cost, both as a function of p, simplify it as as abest you can, then dProfit/dp=0 and solve for p. The factoring will take care of itself...you need to end up with a quadratic in standard form.

- Calc -
**Matt**, Sunday, November 25, 2007 at 3:27pmI did simplify P' to be P'=-2p+33(p-9+100)+1(-p^2+33p+9) now I have to set the derivative,P', equal to zero and I do not know how to solve it.

- Calc -
**Ben**, Sunday, November 25, 2007 at 3:31pmWe did what Matt said but we do not know what to do next, our teacher told us to set the derivative equal to zero and then factor to get more than one answer and say which one maximizes the profit but we cannot solve P'=0

- Calc -
- Calc -
**bobpursley**, Sunday, November 25, 2007 at 4:56pmP'=-2p+33(p-9+100)+1(-p^2+33p+9)=0

I didn't check that to make certain the derivative is correct. But if it is, gather terms, and

-p^2+ (-2+33+33)p + 3300 +9=0

check that.

Now use the quadratic equation to find the values of p that solve it.