Posted by Andrew on Friday, November 23, 2007 at 10:16pm.
1. Realize that NaOH and CH3COOH is the reaction of a strong base and a weak acid. Write and balance the equation. The products are CH3COONa and HOH.
2. Determine mols NaOH and mols CH3COOH. mols = L x M.
3. From the equation, determine mols CH3COONa formed. That is a salt. I haven't worked the problem but you PROBABLY will have an excess of CH3COOH which will make a buffer of CH3COOH and CH3COONa (a weak acid and its salt) and all of the NaOH will be used.
4. Then use the Henderson-Hasselbalch equation. pH = pKa + log [(base}/(acid)]
Show your work if you get stuck.
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