Posted by **Brittany** on Friday, November 23, 2007 at 5:59pm.

A person who is 6 feet tall walks away from a 50-foot silo toward the tip of the silo's shadow. At a distance of 32 feet from the silo, the person's shadow begins to emerge beyond the silo's shadow.How much farther must the person walk to be completely out of the silo's shadow?

- Algebra II -
**Michael**, Friday, November 23, 2007 at 6:57pm
You need to set up the situation with a diagram using similar triangles. Then, use the Pythagorean Theorem.

- Algebra II -
**drwls**, Friday, November 23, 2007 at 8:33pm
Let x be the additional distance to the end of the shadow. Using the similar triangles method suggested by Michael, the ratios of the two per[pendicular sides are:

50/(32+x)= 6/x

Solve for x.

50 x = 192 + 6x

44 x = 192

x = ?

## Answer this Question

## Related Questions

- College Algebra - A person who is 6 feet tall walks away from a 50-foot tower ...
- College Algebra - A person who is 6 feet tall walks away from flagpole toward ...
- Math - A round silo is 55 feet tall and has a 18 foot radius. How high would a ...
- geometry - camera is 4 ft 6 inched off the ground 18 feet away from a silo, how ...
- Algebra - A large grain silo is to be constructed in the shape of a circular ...
- Geometry - Carl is looking to buy a farm. While looking at a potential property...
- Math - Charlie is making a toy silo for his children. The silos height is three ...
- Quantitative Reasoning (math) - A round silo is 60 ft tall and has a 15 ft ...
- Algebra - I posted this earlier but the number was wrong. I don't know why it ...
- Math Urgent help please - A lamppost casts a shadow of a man who is standing 15 ...

More Related Questions