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April 16, 2014

April 16, 2014

Posted by **Brittany** on Friday, November 23, 2007 at 5:59pm.

- Algebra II -
**Michael**, Friday, November 23, 2007 at 6:57pmYou need to set up the situation with a diagram using similar triangles. Then, use the Pythagorean Theorem.

- Algebra II -
**drwls**, Friday, November 23, 2007 at 8:33pmLet x be the additional distance to the end of the shadow. Using the similar triangles method suggested by Michael, the ratios of the two per[pendicular sides are:

50/(32+x)= 6/x

Solve for x.

50 x = 192 + 6x

44 x = 192

x = ?

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