Posted by **Anonymous** on Friday, November 23, 2007 at 2:30am.

One kilogram of an ideal gas is heated from 27*C to 327*C. If the volume of the gas remains constant, the ratio of the pressure of the gas before heating to the pressure after is

a. 1:4

b. 1:3

c. 1:2

d. 1:1

Work:

1atm/293K=P/(327+273)

P=2 So, from what I got, I think the answer is c.

- physics -
**drwls**, Friday, November 23, 2007 at 8:04am
Yes, the absolute temperature T doubles. Since V is constant, the pressure also doubles. The answer is (c)

Your formula should be

P1/T1 = {P2/T2)

P2/P1 = T2/T1 = (327+273)/(27+273)

= 600/300

P1 does not have to be 1 atm, and you did not calculate T1 correctly. It is 300, not 293.

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