Posted by Anonymous on Thursday, November 22, 2007 at 9:01pm.
For the following equation, why cannot I not solve it? I keep getting an error.
2cosx - 3 = 0
I first isolated for "x"
2cosx-3 = 0
(2cosx/2) = (3/2)
x = cos^-1(3/2)
x = error? why?
My textbook answer:
30 and 330 degrees
Answer This Question
More Related Questions
- trig - prove that (2cosx+1)(2cosx-1)= 1 +2cos2x
- Math - Find the limit of (2cosx+3cosx-2)/(2cosx-1)as x tends to pi/3.
- math - tanx+secx=2cosx (sinx/cosx)+ (1/cosx)=2cosx (sinx+1)/cosx =2cosx ...
- Mathj C30 - Solving Equations Containing Circular Functions : Solve 2cosx sinx...
- Trig - cos2x(2cosx+1)=0 Solve for x.
- Pre Calculus - Having trouble verifying this identity... cscxtanx + secx= 2cosx ...
- trig - how do you graph the equation y=-2cosx?
- Trig - Solve for x in the interval [0,2pi) sin^2x+2cosx=2
- derivatives - x^2cosx-2xsinx-2cosx
- math, trig - Graph one period of the following function. Show all work . y=2sinx...