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October 1, 2014

October 1, 2014

Posted by **Anonymous** on Thursday, November 22, 2007 at 9:01pm.

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2cosx - 3 = 0

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I first isolated for "x"

2cosx-3 = 0

(2cosx/2) = (3/2)

x = cos^-1(3/2)

x = error? why?

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My textbook answer:

30 and 330 degrees

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- Math - Solving for Trig Equations -
**Reiny**, Thursday, November 22, 2007 at 10:08pmMake sure you copied the question correctly.

The way it stands

cos x = 3/2 has indeed no solution

(the sine and cosine function does not exceed a value >1 or < -1

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