Posted by Anonymous on Thursday, November 22, 2007 at 5:35pm.
Solve the following equation for
0 less than and/or equal to "x" less than and/or equal to 360
cos^2x - 1 = sin^2x
cos^2x - 1 - sin^2x = 0
cos^2x - 1 - (1 - cos^2x) = 0
cos^2x - 1 - 1 + cos^2x = 0
2cos^2x - 2 = 0
cos^2x = -1
cosx = square root of -1
And I can't do anything with this now...what am I doing wrong?
0, 180, 360
- Math - Solving for Trig Equations - bobpursley, Thursday, November 22, 2007 at 5:40pm
On the fourth/fifth line, you erred. When you add 2 to both sides, the right side is positive, not negative.
cos x= +- 1
giving 1, 180,360
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