Thursday
December 18, 2014

Homework Help: Math - Solving Trig Equations

Posted by Anonymous on Wednesday, November 21, 2007 at 8:23pm.

Solve each equation on the interval:
0 is less than and equal to theta is less than and equal to 360


--
2sin2x = 1
--



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My Answers:
Let y represent 2x
2siny = 1
2siny/2 = 1/2
siny = 1/2
y = sin^-1(1/2)
y = 30

2x = 30
2x/2 = 30/2
x = 15 (Quadrant 1)

Quadrant 2
180 - theta
= 180 - 30
= 150

2x = 150
2x/2 = 150/2
x = 75

Therefore, x = 15 and 75 degrees
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Book's Answers:
15, 75, 195, 255


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My Problem:
I'm asking how do you get 195 and 255 degrees if the equation is sin and it's positive and the restriction is between 0 and 360 degrees, so angles are on Quadrant 1 and 2?

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