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April 19, 2014

April 19, 2014

Posted by **Mike** on Wednesday, November 21, 2007 at 6:32pm.

A movie theater had a certain number of tickets to give away. Five people got the tickets. The first got one third of the tickets, the second got one fourth of the tickets, and the third got one fifth of the tickets. The fourth person got eight tickets and there were five tickets left for the fifth person. Find the total number of tickets given away.

- Alebra -
**Michael**, Wednesday, November 21, 2007 at 6:37pmYou'll have to set up an equation to model this situation. Let t be the total number of tickets, and see what you can come up with. (Hint: The word "of" is the same as "multiplied by.")

- Alebra -
**john**, Wednesday, November 21, 2007 at 6:47pmI think I got it...so the equation would look like 1/3(t)+1/4(t)+1/5(t)+8+5=total #??

- Alebra -
**Michael**, Wednesday, November 21, 2007 at 6:55pmRight, but don't forget that t is our total number of tickets, so it should be...

1/3(t)+1/4(t)+1/5(t)+8+5 = t

Then, solve for t. If you have any more questions, I'll be glad to help.

- Alebra -
**john**, Wednesday, November 21, 2007 at 7:18pmOkay so after isolating "t" on one side of the equation I came up with

47/60(t)=t-13...after subtracting "t"...I got

-13/60(t)=-13..after doing the division found out t=60!..think its right because I plugged it back into my orginal equation and found 1/4,1/5/,1/3 plus 8 and 5 equals 60...did I get it right?!

- Alebra -
**Michael**, Wednesday, November 21, 2007 at 7:41pmThat's right. There were 60 tickets. Good job! :)

- Alebra -

- Alebra -

- Alebra -

- Alebra -

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