Math  Solving Trig Equations
posted by Anonymous on .
Solve each equation for 0 is less than and equal to "x" is less than and equal to 360
3sinx = 2cos^{2}x

I don't know how to solve this equation...this is what I have, but I don't know if I'm on the right track or not
3sinx = 1  2sin^{2}x
3sinx  1 + 2sin^{2}x = 0
2sin^{2}x + 3sinx  1 = 0
sinx(3 + 2sinx) = 1
...and if I am, what do I do next now?

The answers are:
30 and 150 degrees

3sinx = 2cos^2(x)
I believe you've treated this as cos(2x) and expanded it as a doubleangle identity. However, you can't do this because the cosine function is being squared. The 2 is not being multiplied by the x.
I'm working on it... 
Start by recalling the most important identity. My math teacher calls this "the #1 Identity."
sin^2(x) + cos^2(x) = 1
We want to simplify our trig equation by writing everything in terms of sine. Let's solve the #1 Identity for cos^2(x) because we have that in our trig equation.
cos^2(x) = 1  sin^2(x)
Plug that into the trig equation, and see what you can get from there. Let me know if you get stuck along the way. 
wow I forgot about that identity, thank you!
But, I'm still stuck...
I get
cos^2x + sin^2x = 1
I can't use any compound identities for this...I don't know how to isolate for either cos or sin... 
The only identity you need it the #1 Identity.
Plugging in 1  sin^2(x) for cos^2(x), you should get...
3sinx = 2(1  sin^2(x))
Use the distributive property, collect everything on the left, and then factor. 
The only identity you need is the #1 Identity.
Plugging in 1  sin^2(x) for cos^2(x), you should get...
3sinx = 2(1  sin^2(x))
Use the distributive property, collect everything on the left, and then factor. 
thanks, I solved it :)

Glad to be of service. :)

Is d answer 90degree