Posted by beckii on .
What average force is required to stop an 1100kg car in 8.0 s if it is traveling at 95 km/h?
i got the answer to be 13062.5 N. i don't think that's right...

physics 
bobpursley,
Impluse= change in momentum
Force*time= 1100*26.4m/s
I don't get your numbers, about one fourth of that. Did your conversion of km/hr to m/s same as mine?
Here is a neat trick. Put in the google search window...
1100kg*95km/hr* 1/(8seconds) in newtons 
physics 
drwls,
First convert kg/h to m/s
95 km/h = (95000 m/h)/(3600) s/h
= 26.4 m/s
Force x Time = momentum change
= 1100*26.4 = 2.90*10^4 kg m/s
Divide that by the time interval (8.0s) to get the average force in Newtons 
physics 
osvaldo,
Change velocity from km/h to m/s
95 km/h*(1000 m/km)*(1 h/3600 s)= 26.4 m/s
a=ΔV/Δt=26.4/8=3.3 m/s^2
ΣF=m*a=1100kg*3.3 m/s^2=3630 N
Tada!