Saturday

August 23, 2014

August 23, 2014

Posted by **Claire** on Wednesday, November 21, 2007 at 4:06pm.

log2 xy = 7

log2 (x^2/y) = 5

2. If log y x =a and log z x=b where x is not equal to 1, express the following in terms of a and b:

logy (yz)

Solve the following simultaneous equations:

y = 2 log3 x

y+1 = log3 9x

Thanks! I tried to work them out but I couldn't!

- maths pls help -
**bobpursley**, Wednesday, November 21, 2007 at 4:27pmTry this on the first set:

log (xy)= logx + logy

log (x^2y)= 2logx + log2

Those ought to help.

Try that also on the second.

On the third,

y+1= log3 9x = log33^2 x= 2 + log3 x

y-1= log3 x

but y= 2log3 x then solve.

- maths pls help -
**Claire**, Wednesday, November 21, 2007 at 4:40pmI still cannot work them out!!

- maths pls help -
**Michael**, Wednesday, November 21, 2007 at 4:46pmWhat problems are you having? Where are you getting stuck?

- maths pls help -
**Claire**, Wednesday, November 21, 2007 at 4:49pmI don't know. I simply cannot agree with the answers and I have tried to work them out many times

- maths pls help -
- maths pls help -
**Jenny**, Wednesday, November 21, 2007 at 7:18pmI am having problems in mmeasuring.

- maths pls help -

**Related Questions**

Logarithms - I'm working on logarithmic equations and I'm stuck on how my book ...

Math - The problem I have to solve is log with base 2 ^6 multiply by log base 6...

Math - Logarithmic - Solve: 2^(5x-6) = 7 My work: log^(5x-6) = log7 5x - 6(log2...

maths - which three statements are true? a) if x= -10^4 then log 10 = -4 b)if x...

maths - which three statements are true? a) if x= -10^4 then log 10 = -4 b)if x...

Precalculus - More log/exponential equations log2 x + log2(x+2) =3

math30 - 1.Use the laws of logarithms to express log2 (6) – log2 (3) + 2log2 (...

mathematics -logs - which three statements are true? a) if x= -10^4 then log 10...

Algebra II - Please check answers: Use the equation of the exponential function ...

math - solve the equation log2(x+4)-log4x=2 the 2 and 4 are lower than the g ...