what is theoxidation state of sulfur in Fe2(SO4)3?
Using the rules...
S= +6 do you agree?
indeed it is +6. From this compound, there are several things you can get out from it:
The Iron must be Fe(III) and not Fe(II).
The net charge = 0 so 2Fe(III) = +6 so 3(SO4)must = -6 so (SO4) must = -2
Oxygen = -2 because it only contains 6 valence electron (missing 2 to be full).
4 Oxygen = -8 so Sulfur - 8 = -2
Add 8 on both sides as a math equation and you get Sulfur = 6.
To determine the oxidation state of sulfur in Fe2(SO4)3, we need to consider the overall charge of the molecule and the known oxidation states of other atoms involved.
1. Start by assigning the known oxidation states of the atoms. In this case, iron (Fe) has a known oxidation state of +3.
2. The overall charge of the sulfate ion (SO4) is -2. Since there are three sulfate ions in the formula, the total charge is -6.
3. Now, let's assume x as the oxidation state of sulfur.
4. We can set up the equation using the oxidation states and the overall charge:
2*(+3) + x + 3*(-2) = 0
5. Simplify the equation:
+6 + x - 6 = 0
6. Combine like terms:
x = 0
So, the oxidation state of sulfur (S) in Fe2(SO4)3 is 0.
To determine the oxidation state of sulfur in Fe2(SO4)3, we need to analyze the oxidation states of the other elements present.
We start by considering the overall charge of the compound, which is 0 since there are no charged ions mentioned. The sum of the oxidation states of all elements in a compound must equal the compound's overall charge.
Let's break down the compound: Fe2(SO4)3.
The oxidation state of iron (Fe) is usually +2 or +3, but in this case, we have two iron atoms present. Since the compound is neutral (0 charge), the sum of the oxidation states of both iron atoms will equal 0. Therefore, each iron atom must have an oxidation state of +3.
Now, let's analyze the sulfate ion (SO4^2-). The entire sulfate ion has an overall charge of -2. Since there are three sulfate ions in the formula, their combined charge is -6 (2- x 3).
To calculate the oxidation state for sulfur (S), we can use the following equation:
Oxidation state of sulfur + 4(-2) = -6
Simplifying this equation:
Oxidation state of sulfur - 8 = -6
Oxidation state of sulfur = -6 + 8
Oxidation state of sulfur = +2
Therefore, the oxidation state of sulfur in Fe2(SO4)3 is +2.