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March 31, 2015

March 31, 2015

Posted by **Courtney** on Tuesday, November 20, 2007 at 11:18pm.

- College Algebra -
**DrBob222**, Wednesday, November 21, 2007 at 12:17amThe problem isn't clear if the wind was blowing on the first part of the trip. I have assumed it was not.

distance = rate x time or

time = d/r

For the trip out, we have time = 1500/600

For the trip back we have 1200/r. The times are the same so we set them equal.

1500/600 = 1200/r

solve for r. I have 480 km/hr so the wind must have been blowing 600-48- = 120 km/hr.

You can check this by checking the time.

time for trip out is 1500/600 = 2.5 hrs.

time for trip back is 1200/480 =2.5 hrs.

If the wind blew on the way out you must make some adjustments to the above.

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