How many moles of CaCO3 are present in 30.6g of it ?
mols = grams/molar mass.
You have to determine the molar mass of CaCO3, by getting the molar mass of Ca and the molar mass of C, and the molar mass of O multiplied by 3 (since there are 3 oxygen atoms).
You would get 100.087 g/mol.
You would then do the mass/molar mass.
30.6/100.87 = your answer
To determine the number of moles of CaCO3 present in 30.6g, we need to use the molar mass of CaCO3.
The molar mass of CaCO3 is calculated by adding up the atomic masses of calcium (Ca), carbon (C), and three oxygen (O) atoms:
Molar mass of CaCO3 = (atomic mass of Ca) + (atomic mass of C) + 3 * (atomic mass of O)
The atomic masses of Ca, C, and O are approximately 40.08 g/mol, 12.01 g/mol, and 16.00 g/mol respectively. By substituting these values into the equation, we can calculate the molar mass of CaCO3:
Molar mass of CaCO3 = 40.08 g/mol + 12.01 g/mol + 3 * 16.00 g/mol
= 40.08 g/mol + 12.01 g/mol + 48.00 g/mol
= 100.09 g/mol
Now, we can use the molar mass of CaCO3 to calculate the number of moles present in 30.6g:
Number of moles = Mass of substance / Molar mass
Number of moles of CaCO3 = 30.6g / 100.09 g/mol
Calculating this value gives us the answer to your question.