Saturday

October 25, 2014

October 25, 2014

Posted by **JerriAnne** on Tuesday, November 20, 2007 at 8:55pm.

Given a right triangle with B=4 and

C=11 find A appoximated to three decimal places.

- math-triangle help -
**Anonymous**, Tuesday, November 20, 2007 at 8:59pmUse the Pythagorean theorem, r^2 = y^2 + x^2

r^2

= 4^2 + 11^2

= 16 + 121

= 137

= Square root of 137

= 11.705

- math-triangle help -
**Kelly**, Wednesday, November 21, 2007 at 2:58pmThis is how I would do it.

Pythagorean theorem: a2 + b2 = c2.

a^2 + 4^2 = 11^2

a^2 +16 = 105

subtract both sides by 16

a^2 - 16 = 105 - 16

a^2 = 105

a = sqrt 105

a = 10.247

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