posted by mel on .
in the equation 2SO2 + O2 -> 2SO3
how do you find if work done is >, <, or = to 0?
The system has 3 mols gas on the left and 2 on the right; therefore, the system decreases in volume which means work is done ON the system if the pressure is constant. Work done ON the system is + (or > 0). Check my thinking.