Posted by Tracy on Sunday, November 18, 2007 at 5:59pm.
The initial CoCl2.6H2O probably is oxidized by the H2O2 to Co^+3 which is what you have in the [Co(NH3)5Cl]Cl2, the other product of H2O2 is H2O. The NH4OH added is easier to handle if you do it as NH3 + H2O (same thing but much easier to see how the NH3 gets into the coordination sphere for Co). The NH4Cl/NH4OH is there as a buffer as well as to furnish the NH3 for the Co coordination. I would leave the NH4Cl as NH4Cl. And the HCl is there to furnish the Cl^- for the extra Cl that must be present for the ionic charge increase from +2 to +3 for Co. I hope these hints are sufficient.
Thanks alot = )
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