Posted by **Mike** on Sunday, November 18, 2007 at 5:19pm.

A geosynchronous equatorial orbiting satellite orbits 22,300 miles above the equator of Earth. It completes one full revolution each 24 hours. Assume Earth's radius is 3960 miles. a. How far will the GEO satellite travel in one day? b. What is the satellite's linear velcoity in miles per hour?

- Math -
**Michael**, Sunday, November 18, 2007 at 5:48pm
a. The GEO satellite's path is circular. The distance on a circular path is the circumference. C = 2 (pi) (r) = 2 (pi) (3960) = 7920pi

b. Distance = Rate * Time

Rate = Distance/Time = 7920pi / 24 hours = 330pi

I'm 100% sure on a, 90% on b.

- Math -
**Reiny**, Sunday, November 18, 2007 at 11:52pm
for b)

linear velocity = angular velocity x radius

the angl vel. = 2pi/24 rad/hr

so linear vel. = 2pi/24(26260) miles/hr

= 6875 mph

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