Posted by **Anonymous** on Sunday, November 18, 2007 at 12:46am.

At what point(s) does the curve defined by x^2-6x=6-6y^2 have horizontal tangents?

I took the derivative and solved for y'. I got y'=-1/6x/y+1/2y. hmm...what am I suppose to do?

- Calculus -
**Reiny**, Sunday, November 18, 2007 at 1:24am
leave your derivative as

dy/dx = (2x-6)/(-12y) after you differentiated implicitly.

then (2x-6)/(-12y) = 0 can only be true if

2x-6 = 0

x = 3 now put that back into the original equation to get y = ...

your equation will be y = that value

- Calculus -
**Anonymous**, Sunday, November 18, 2007 at 11:51am
would it by (2,sqrt(10)/2)?

## Answer This Question

## Related Questions

- Math - 1. f(x)=x^2(e^x) find a point where the tangent is horizontal. The answer...
- math - consider the curve defined by the equation y=a(x^2)+bx+c. Take a point(h,...
- calculus - there are two tangents lines to the curve f(x) = 3x^2 that pass ...
- Calculus - Consider the curve defined by y + cosy = x +1 for 0 =< y =< 2pi...
- calculus - the line y=x-c touches the ellipse 9x^2 + 16y^2 = 144. Find the value...
- Calculus questions..really need help, please! - 1) Find the value of the lim(x-&...
- 12th Grade Calculus - 1. a.) Find an equation for the line perpendicular to the ...
- Calculus (Help) - Also I would like to know how to set this problem up in ...
- AP Calc - Find the equation of ALL horizontal tangents to the curve y^2=x^2+4/x...
- calculus - Consider the curve defined by 2y^3+6X^2(y)- 12x^2 +6y=1 . a. Show ...

More Related Questions