Posted by Anonymous on Sunday, November 18, 2007 at 12:40am.
An equation of the line tangent to the graph of y=(2x+3)/(3x2) at the point (1,5) is...do I take the derivative of y=(2x+3)/(3x2) to find the slope and then plug that into y5=m(x1)?

Calculus  Reiny, Sunday, November 18, 2007 at 1:30am
yes

Calculus  Anonymous, Sunday, November 18, 2007 at 12:03pm
I took the derivative and got 10/(3x2)^2. So...I plug in 1 in the x. Then, I get the slope to be 10. Finally I plug it in (1,5) and m=10 to get y=10x+15. Is that correct?

Calculus  Reiny, Sunday, November 18, 2007 at 2:55pm
check your derivative
I had y' = 13/(3x2^2
so the slope would be 13

Calculus  qwerrtjdjdjswb, Sunday, November 18, 2012 at 8:49pm
How??????

Calculus  Tim Tittles, Sunday, November 18, 2012 at 8:54pm
I don't know. Why are you asking me?

Calculus  Remi, Monday, April 15, 2013 at 9:55pm
I believe the answer is y = 13x + 18. In the question I had, one of the choices was 13x + y = 18, which is what y = 13x + 18 equals. I got 13 for slope, then plugged it in to get y 5 = 13x + 13

Calculus  Kaitlin, Wednesday, January 6, 2016 at 8:58am
Y=13+18
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