Posted by Anonymous on Sunday, November 18, 2007 at 12:02am.
integral x cosxdx
u =x dv = cosxdx
du = 1 v = sin x
Answer: x sin x + cosx
du = 2e^2x v=-cosx
Answer -cos x*e^-2x +Integral 2 cos x e^2x
Now use the same integration by parts trick one more time to get a term that contains sin x e^2x on the right. Since you already have the same term on the left side, with a different coefficient, you can move all the sin x e^2x terms to one side of the equation and solve for it.
Can you check if I did it correctly?
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