Posted by **Chem** on Saturday, November 17, 2007 at 1:06pm.

N2 + 3H2 --> 2NH3

At 25Â°C (delta)Ho = -92.22 kJ and (delta)So = -198.53 J/K. Using this information, calculate the equilibrium constant for the reaction at 2.43x10^2Â°C. (R = 8.314 J/K)

Apparently the way I'm doing it is wrong:

I divide 198.53 by 1000 then multiply by 298 to get delta(S). Then I subtract this from delta(H) to get delta(G). Then I multiply 516 with .008314... I take this answer and divide delta(G) by it, then multiply by -1. I take this to the e power... Then I use the equation Kc = (RT)^-n * Kp to get the equilibrium constant. However my answer is still wrong.

- Dan -
**DrBob222**, Saturday, November 17, 2007 at 1:33pm
or mike or whomever,

Two points:

1. How do you know to calculate Kc instead of Kp? The problem doesn't specify which. Since this is a gaseous reaction, Kp may be what they are looking for.

2. Have you tried the van't Hoff equation. You have delta H and one T so the van't Hoff equation can be used to calculate K at any other T.

## Answer this Question

## Related Questions

- Mike - N2 + 3H2 --> 2NH3 At 25Â°C (delta)Ho = -92.22 kJ and (delta)So = -198....
- Chemistry - Consider the reaction 2 SO2(g) + O2(g) in equilibrium with 2 SO3(g...
- Chem, help please - Consider the reaction N2 + 3H2 in equilibrium with 2 NH3 . ...
- Chemistry!!! - Consider the rxn during the Haber Process: N2 + 3H2 ---> 2NH3 ...
- Chemistry - Consider the rxn during the Haber Process: N2 + 3H2 ---> 2NH3 The...
- Chemistry - 2M +6HCl–>2MCl+3H2 Delta H= -638.0 Kj HClg—>HCl aq= Delta H -...
- Chemistry - Calculate the enthalpy of the reaction 2B2H6 + 6O2=2B2O3 +6H2O given...
- Chemistry - Clapeyron equation: dp/dT = ΔS / ΔV My textbook says, ...
- Chemistry - The following standard free energies are given for 25 degrees ...
- AP Chemisty - N2(g)+3F2 yields 2Nf3(g) Delta H(degree)298=-264KJ mol-1;Delta S(...

More Related Questions