Algebra
posted by Soly on .
Can you please check my answer:
Solve the problem.
A person with no more than $4000 to invest plans to place the money in two investments, telecommunications and pharmaceuticals. The telecommunications investment is to be no more than 3 times the pharmaceuticals investment. Write a system of inequalities to describe the situation. Let x=amount to be invested in telecommunications and y=amount to be invested in pharmaceuticals.
I got:
x+y=4000
x< or equal to 3y
x> or equal to 0
y> or equal to 0

NO MORE THAN results in x+y LESS THAN OR EQUAL to 4000.