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December 18, 2014

December 18, 2014

Posted by **Soly** on Saturday, November 17, 2007 at 12:51am.

Solve the problem.

A person with no more than $4000 to invest plans to place the money in two investments, telecommunications and pharmaceuticals. The telecommunications investment is to be no more than 3 times the pharmaceuticals investment. Write a system of inequalities to describe the situation. Let x=amount to be invested in telecommunications and y=amount to be invested in pharmaceuticals.

I got:

x+y=4000

x< or equal to 3y

x> or equal to 0

y> or equal to 0

- Algebra -
**Cindy**, Saturday, November 17, 2007 at 7:38amNO MORE THAN results in x+y LESS THAN OR EQUAL to 4000.

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