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December 20, 2014

December 20, 2014

Posted by **Alicia** on Friday, November 16, 2007 at 8:20pm.

5x+6y=18 solve for y

6y=18-5

y=3-5/6x

- college algebra -
**Reiny**, Friday, November 16, 2007 at 8:22pmok

- college algebra -
**Michael**, Friday, November 16, 2007 at 8:25pmClose, except you have to subtract 5x from both sides. (You just subtracted 5 from the right side.)

5x + 6y = 18

Subtract 5x from both sides.

6y = 18 - 5x

Divide by 16

y = (18-5x)/6

or 3 - (5/6)x

All right. I think you must have done it correctly, and you just forgot your x in the second step. Good job. :)

- college algebra -
**Michael**, Friday, November 16, 2007 at 8:26pmOops... that should say...

6y = 18 - 5x

Divide by 6 (not 16).

- college algebra -
**Alicia**, Friday, November 16, 2007 at 11:32pmokay so using y = (-5/6)x + 3 how do i find the corresponding value for y when x = 12?

- college algebra -
**Michael**, Saturday, November 17, 2007 at 2:13pmSimply plug in 12 for x...

y = (-5/6)(12) + 3 = -10 + 3 = -7

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