Volume of stock solution
a. 5.0mL b.10.0mL c.15.0mL d.20.0mL
Prepare 25mL of each of the four different dilute solution
Concentration of stock- 1.01E-5
Calculate molarity for a,b,c,d
Molarity=m1V1/V2
for a would the answer be 2.02E6?????
(1.01E-5)(5.0)/(25.0)
Yes, the answer is what you posted EXCEPT the exponenet is -6 and not +6. Also, you don't say if th e stock solution is molar, molal, or what. Your answer is ok if the stock solution is 1.01E-5 MOLAR
Its Molar. Thanks
If for a. the concentration is 2.02E-6, Wavelength at 630, Absorbance is .216, how would I find the %T.
Absorbance = 1/T OR 100/%T.
What do you mean? I know the equation is %T=It/Io*100
A=log(Io/It)=-logT
I don't know how to use it and plug in the information I have.
Use your calculator.
A = log (1/T)
0.216 = log (1/T)
1.644 = 1/T
T = 0.608
%T = 60.8%
To calculate the molarity for each of the dilute solutions (a, b, c, d), we can use the formula:
Molarity (M) = (m1V1) / V2
where:
m1 = concentration of the stock solution
V1 = volume of stock solution used
V2 = final volume of the dilute solution
Given:
Concentration of the stock solution (m1) = 1.01E-5
Volume of stock solution used (V1) = 5.0 mL
Final volume of the dilute solution (V2) = 25.0 mL
Now let's calculate the molarity for option a:
Molarity (a) = (1.01E-5 * 5.0) / 25.0
Molarity (a) = 5.05E-6 mol/L
Therefore, the molarity for option a is 5.05E-6 mol/L, not 2.02E6.