Posted by jason on Thursday, November 15, 2007 at 10:59pm.
1. Ok. Well you know that 2 angles in the parallelogram have the same angle, right? The opposite angles? And the other 2 angles are the same, right? So let's say the small angle is x. That means there are two angles that are x degrees. Now, if the other angles are 30 degrees more, how would you write that? x+30. So, you have 2 x's and 2 (x+30)s. x+x+(x+30)+(x+30)=360 because there are 360 degrees in the parallelogram. Now solve for x. This will be the degrees for the two small angles. Add 30 to get the amount for the larger ones. Make sense?
ohh.. ^^ thank you :D
now... any1 up for the next 2? ^^
2. Ok. What are the base angles? Well, in an isoceles triangle, two sides are the same length. There is an angle between them. The base angles are the 2 angles that are NOT between them, and they are EQUAL. So, the two base angles are 88 degrees less that the remaining angle. Let's say the remaining angle is x. What would the sum of the other two angles be? If they are 88 less than the remaining angle, won't the two of them add up to x-88? There are 180 degrees in a triangle, so (x-88)+x=180, solve for x.
1) start by drawing one,
on the 2 bigger angles put 30+x
on the 2 smaller angles put x
so you have 30+x+30+x+x+x
so now you have 60+4x
in a parallelogram there are 360 degrees
now put it into an equation
60+4x=360
4x=300
x=75
so if the bigger angles are 30+x then they are 30+75=105
so the angles are 105,105,75,75
3, 1/2, 2, -1.5,-2/3,0.75 put in increasing order
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