Posted by Chemistry on Wednesday, November 14, 2007 at 11:03pm.
I can't draw these on the computer or these boards.
Mg: is the neutral Mg atom.
..
:S: is the neutral S atom.
Now move the two electrons on Mg to the bottom of S. That leaves Mg with no electrons and a 2+ charge and it leaves S with 8 electrons and a 2- charge.
Ba and I are done the same way except the formula is BaI2 so 1 electron from Ba is transferred to one of the I atoms and the other electron from Ba is transferred to the other I atom. Ba then carries a 2+ charge and each I carries a -1 charge.
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