Which has the larger radius N^3- or P^3-?

Please Explain

See my your previous question and my response.

so in my book there is a chart but there is not a number for it so I can see which has a larger radius what is another way to tell which is larger they both have a 3- charge

Look at the placement of N and P on the periodic chart. The electron configuration of N is

7N = 1s2 2s2 2p3 =7 electrons
P is
15P = 1s2 2s2 2p6 3s2 3p3 = 15 electrons.
You know that neutral P is larger than neutral N
a) because size generally decreases as you down the table--why?
b)because we are adding extra shells. Look at N and P. N has nothing in the 3rd shell but P has 5 electrons in the 3rd shell.
SO, if neutral N is smaller than neutral P, then it must follow that N3- must be smaller than P3-? right?

correct thank you for the help

To determine which ion, N^3- or P^3-, has the larger radius, we need to consider their respective positions on the periodic table.

N (nitrogen) is in the second row of the periodic table, while P (phosphorus) is in the third row. As we move down a group in the periodic table, the atomic radius generally increases. Therefore, N should have a smaller radius than P.

Now, let's consider the charges on the ions. Both N^3- and P^3- have a charge of -3, indicating that they have gained three electrons. When an atom gains electrons, the electron-electron repulsion increases, causing the electron cloud to expand. This expansion leads to an increase in atomic radius.

Since both N^3- and P^3- have gained three electrons, we can assume that they have similar electron cloud expansions. However, since P is larger in size due to its position in the third row of the periodic table, it will have a larger overall radius than N.

Therefore, P^3- has a larger radius than N^3-.