Which of the three isomers: NOBr, OBrN, or ONBr, is the most stable? Where should I start??

The least electronegative element usually is the central element. The most energetically favorable structure is the one with zero formal charge on the atoms (or as near zero as possible).

Write the three stuctures, determine which atom is the least electronegative, and determine the formal charges on the atoms in each structure.

Okay so would the answer be oBrN??

To determine the relative stability of isomers, it is helpful to consider the molecular structure, bond types, and electronegativity of the atoms involved.

First, let's analyze the three isomers of NOBr, OBrN, and ONBr:

1. NOBr: In this isomer, nitrogen (N) is bonded to oxygen (O) via a double bond, and bromine (Br) is attached to nitrogen. The molecule can be represented as O=N-Br.

2. OBrN: In this isomer, oxygen is bonded to bromine, and nitrogen is attached to bromine. The molecule can be represented as O-Br=N.

3. ONBr: In this isomer, oxygen is bonded to nitrogen, and bromine is attached to nitrogen. The molecule can be represented as O-N=Br.

To determine the most stable isomer, consider the electronegativity difference between the atoms:

1. Nitrogen is more electronegative than bromine, so the double bond in NOBr is polar, with the oxygen having a partial positive charge and the bromine having a partial negative charge.

2. Oxygen is more electronegative than bromine, so the bond in OBrN is polar, with the nitrogen having a partial positive charge and the bromine having a partial negative charge.

3. Since bromine is more electronegative than nitrogen, the bond in ONBr is polar, with the oxygen having a partial negative charge and the nitrogen having a partial positive charge.

Now, let's consider the stability of these isomers based on the electronegativity difference and the overall electron arrangement.

Since oxygen is more electronegative than nitrogen, the oxygen atom in ONBr will stabilize the partial positive charge on nitrogen through electron donation. This results in a more stable arrangement compared to the other two isomers.

Therefore, based on the analysis, ONBr is the most stable isomer among NOBr, OBrN, and ONBr due to the electron-donating effect of oxygen stabilizing the partial positive charge on nitrogen.

No, You have the central atom as the MOST electronegative but you want the central atom to be the LEAST electronegative. Also, OBrN has formal charges on the O of +1, on Br of +1, and -2 on N. Besides the -2 not being a small formal charge, the same charge on adjacent atoms is highly unlikely. In addition, N has only 1 bond and O has only 1 bond. Does one of the other structures have lower formal charges, have the central atom as the least electronegative element and have zero or near zero formal charges on the atoms (as well as O with 2 bonds, Br with 1 and N with 3)?