Posted by Lindsay on Wednesday, November 14, 2007 at 8:04pm.
NetForce=ma or
a= netforce/m
distance= 1/2 a t^2, use a above, solve for net force. Change cm to m
I come up with 13.6 N as my net force. Is this correct?
netforce= 2*distance/time=2*.85/time^2=13.6N
Here's what you know, m=2.0 kg, vi=0m/s,Dx=.85 m, Dt=5 s, to find a, use the formula Dx = vi(Dt) + 1/2a(Dt)2,0.85=0(.5)+1/2a(.50)^2, solve for a, a=6.8 m/s^2. Now use the formula F = ma, F=2.0*6.8, solve for F, F=14 N.
Here's what you know, m=2.0 kg, vi=0m/s,Dx=.85 m, Dt=5 s, to find a, use the formula Dx = vi(Dt) + 1/2a(Dt)2,0.85=0(.5)+1/2a(.50)^2, solve for a, a=6.8 m/s^2. Now use the formula F = ma, F=2.0*6.8, solve for F, F=14 N.
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