What is the length of a simple pendulum that marks seconds by completing a full swing from left to right and then back again every 2.0s?
explain plz
i know u use this formula T=2pi(L/g)^1/2
but i'm not getting the right answer
That is the correct formula
2 = 2 pi (L/g)^1/2
4 = 4 pi^2 (L/g)
L/g = 1/pi^2
L = 9.8/9.87 = 0.99 m
To calculate the length of a simple pendulum that completes a full swing from left to right and back in 2.0 seconds, we can use the equation for the period of a simple pendulum:
T = 2π √(L / g)
where:
T is the period of the pendulum,
L is the length of the pendulum, and
g is the acceleration due to gravity (approximately 9.8 m/s²).
We can rearrange the equation to solve for L:
L = (g × T²) / (4π²)
Now, let's plug in the values:
T = 2.0 s
g = 9.8 m/s²
L = (9.8 m/s² × (2.0 s)²) / (4π²)
L ≈ (9.8 m/s² × 4.0 s²) / (4π²)
L ≈ 39.2 m²/s² / (4π²)
Using a calculator, we can evaluate the expression:
L ≈ 0.994 m
Therefore, the length of the pendulum that marks seconds by completing a full swing in 2.0 seconds is approximately 0.994 meters.