Posted by Mary on Wednesday, November 14, 2007 at 9:36am.
Can you please explain your answer. How did you get blue lamda. Is it because red and green makes blue? How do I find the value of blue lambda?
A mixture of red light (vacuum = 661 nm) and green light (vacuum = 551 nm) shines perpendicularly on a soap film (n = 1.35) that has air on either side. What is the minimum nonzero thickness of the film, so that destructive interference causes it to look red in reflected light?
nm
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Physic please help!  bobpursley, Wednesday, November 14, 2007 at 7:30am
Wouldnt the thickness be blue lamda/4? ?

Physics please explain  drwls, Wednesday, November 14, 2007 at 10:00am
Bob may have meant to say green light, not blue. The wavelength requirement for minimum reflection is given at
http://hyperphysics.phyastr.gsu.edu/hbase/phyopt/soapfilm.html
For normal incidence and first order destructive interference of reflected green light,
2 N d = lambda(green)
N is the index of refraction.

Physics please explain  bobpursley, Wednesday, November 14, 2007 at 11:41am
I meant green. Sorry.
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