Posted by **Anonymous** on Tuesday, November 13, 2007 at 10:52pm.

Dionne is running clockwise. She can run around a circular track in 120 seconds. Basha, running counter-clockwise, meets Dionne every 48 seconds. Sandra runs clockwise and passes Basha every 240 seconds. How often does Sandra meet Dionne in 10 minutes?

- problem solving -
**drwls**, Wednesday, November 14, 2007 at 8:55am
Let Tb be the one-lap time for Basha.

The frequency that Basha and Dionne encounter is

1/48 = 1/120 + 1/Tb, so

1/Tb = 10/480 - 4/480 = 6/480 = 1/80

Tb = 80 seconds

With Sandra and Basha running in opposite directions, and Basha running so fast, they would have to meet more often than every 240 seonds. I believe you made and error stating that Sandra runs clockwise, opposeite to Basha. Check the wording of the problem again.

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