Friday

October 24, 2014

October 24, 2014

Posted by **Anonymous** on Tuesday, November 13, 2007 at 10:52pm.

- problem solving -
**drwls**, Wednesday, November 14, 2007 at 8:55amLet Tb be the one-lap time for Basha.

The frequency that Basha and Dionne encounter is

1/48 = 1/120 + 1/Tb, so

1/Tb = 10/480 - 4/480 = 6/480 = 1/80

Tb = 80 seconds

With Sandra and Basha running in opposite directions, and Basha running so fast, they would have to meet more often than every 240 seonds. I believe you made and error stating that Sandra runs clockwise, opposeite to Basha. Check the wording of the problem again.

**Answer this Question**

**Related Questions**

math - Dionne can run around a circular track in 120 seconds. Basha, running in ...

physics - Suppose runner A starts at the 0 degree mark on a circular track (...

Algebra - Two joggers are running around an oval track in opposite directions. ...

Algebra - Two joggers are running around an oval track in opposite directions. ...

Math - Jess is running around a circular track, one lap every 40 seconds. ...

math - Let AB be a diameter of a circular track. Tom starts from point A running...

English - 1. There are five pictures on the pages. Look at the picture on the ...

math - Michael and mateo begin running around a circular track from the starting...

Math - Two cars run at constant speeds around a one-mile racetrack. If the cars ...

General - The more I read I'm getting confused. Just want to make sure. Winds ...