Posted by Anonymous on Tuesday, November 13, 2007 at 10:52pm.
Dionne is running clockwise. She can run around a circular track in 120 seconds. Basha, running counterclockwise, meets Dionne every 48 seconds. Sandra runs clockwise and passes Basha every 240 seconds. How often does Sandra meet Dionne in 10 minutes?

problem solving  drwls, Wednesday, November 14, 2007 at 8:55am
Let Tb be the onelap time for Basha.
The frequency that Basha and Dionne encounter is
1/48 = 1/120 + 1/Tb, so
1/Tb = 10/480  4/480 = 6/480 = 1/80
Tb = 80 seconds
With Sandra and Basha running in opposite directions, and Basha running so fast, they would have to meet more often than every 240 seonds. I believe you made and error stating that Sandra runs clockwise, opposeite to Basha. Check the wording of the problem again.
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