Help please on how to solve the following problem: If E,N,O,T, and W each represent a different integer, can you find more than one solution to this problem?

Thanks in advance!

I don't know if this is imperative but at the top of the problem it says one + one = two .... not sure if that is a hint or just a title so to speak for the problem...

This is a cryptrythm. Each letter in the one is a numberal, as in 123.

ONE
ONE
____
TWO

Well, O+O is nine or less, when means O is four or less. If O is four, E is 2. O cant be three, because two E's add to it. IF O is 2, E is one.

Lets try both
4N2
4N2
TW4
Now W has to be even, and it cant be 2 or 4, they are used. If W is six, N is three, and T is eight.
W cannot be4 or 2 as they are used. This is solution one.

Solution two. E=1
2N1
2N1
TW2 Again, W has to be even, it cannot be 4 (why?). Try w=six, then n is three, and T is four. Try w=8, N=4, which cannot be, as T will be 4. Try W=(1)0, or N=5. That makes T=5 also.

We have two solutions.

Now here is another for you to work:

SEND
+MORE
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Money

To solve this problem, we need to find different integer values for the variables E, N, O, T, and W. The objective is to determine if there is more than one solution.

To approach this problem, we need to understand the given information about the variables. We know that E, N, O, T, and W each represent a different integer. This means that no two variables can have the same value.

To find the possible integer values for the variables, we can make some observations. Let's look at the word "ONE". If we assign E = 1, then we can represent the word "ONE" as 1, N, 1. However, since each variable must represent a different integer, we cannot assign N = 1.

Let's consider the word "TWO". If we assign W = 2, then we can represent the word "TWO" as T, 2, O. Again, since each variable must represent a different integer, we cannot assign T = 2.

Now, let's consider the word "TEN". If we assign N = 0, then we can represent the word "TEN" as T, E, 0. This means we can assign T = 1 and E = 2, resulting in the solution T = 1, E = 2, and N = 0.

Since the problem asks if there is more than one solution, we have found one possible solution. However, to determine if there are more solutions, we need to explore other possibilities.

Let's consider the word "TEN" again. If we assign N = 4, then we can represent the word "TEN" as T, E, 4. This means we can assign T = 1 and E = 2, resulting in the solution T = 1, E = 2, and N = 4.

Therefore, we have found two different solutions to the problem: T = 1, E = 2, and N = 0, and T = 1, E = 2, and N = 4.

In summary, by analyzing the given constraints and exploring different possibilities, we have found two solutions to the problem.