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December 18, 2014

December 18, 2014

Posted by **John** on Monday, November 12, 2007 at 10:35pm.

Solve by factoring :

x^2-13x= -12

x^2-13x+12= -12 + 12

x^2-13x+12= 0

(x-1)(x-12)= 0

x = 1 , 12

Solve using the square root property:

2x^2-35=15

2x^2-35-15=0

2x^2-50=0

2(x-5)(x+5)=0

x = 5 , -5 Not sure I did this one right.

- Algebra -
**Corin**, Monday, November 12, 2007 at 10:57pmBoth sets of answers are correct. I only wonder if in the second one, you should have used the sq. root property. If you did it that way you would get the exact same answer. I just don't want you to get marked down for not following directions.

here's how to do it using sq. roots:

2x^2-35=15

2x^2=50

x^2=25 <-- sq. root both sides

x=+/- 5

- Algebra -
**John**, Monday, November 12, 2007 at 11:00pmThankyou. I will use the square root way.

Wierd how I got the same answer.

- Algebra -
- Algebra -
**Corin**, Monday, November 12, 2007 at 11:07pmYou're welcome.

If you think about it, it makes since why you got the same answer. The way you did it was right, just not the method they were asking for. There is never just one way to do things in math. :-)

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