Posted by **tasha** on Monday, November 12, 2007 at 1:28pm.

a 15000N car on a hydrolyic lift rests on a cylinder with a piston of radius 0.20M,. if a connecting cylinder with a piston of 0.04M radius is driven by compressed air, what force must be applied to the smaller piston in order to lift the car?

am i doing this right?

(0.04M / 0.20M)* 15000N = 3000N

is this right, if not how do i go about getting the right anwser?

- physics -
**bobpursley**, Monday, November 12, 2007 at 3:34pm
One postion has an area smaller the other, so it must have a force larger than the other.

Area1*force1=pressure=Area2*force2

You have the area/forces reversed, and you did not compute areas, the areas are proportional to the square of radius.

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