Posted by **tasha** on Monday, November 12, 2007 at 1:28pm.

a 15000N car on a hydrolyic lift rests on a cylinder with a piston of radius 0.20M,. if a connecting cylinder with a piston of 0.04M radius is driven by compressed air, what force must be applied to the smaller piston in order to lift the car?

am i doing this right?

(0.04M / 0.20M)* 15000N = 3000N

is this right, if not how do i go about getting the right anwser?

- physics -
**bobpursley**, Monday, November 12, 2007 at 3:34pm
One postion has an area smaller the other, so it must have a force larger than the other.

Area1*force1=pressure=Area2*force2

You have the area/forces reversed, and you did not compute areas, the areas are proportional to the square of radius.

## Answer This Question

## Related Questions

- physics - a 15000N car on a hydrolyic lift rests on a cylinder with a piston of ...
- College Physics - a 15000N car on a hydrolyic lift rests on a cylinder with a ...
- college physics - i just need to know if i got the right answer. plz thankyou a ...
- Physics - A 50 kg piston with a radius of 50 cm floats on a cylinder that is ...
- physics - A car of mass 1420 kg rests on a hydraulic lift with a piston of ...
- Physics - A car of mass 1390 kg rests on a hydraulic lift with a piston of ...
- physics - A cylinder is fitted with a piston that is connected to the bottom by ...
- Physics - A car of mass 1380 kg rests on a hydraulic lift with a piston of ...
- physics - in a car, compressed air exerts a force F1 on a small piston having a ...
- Physics - A hydraulic lift consists of a platform that is supported by a ...

More Related Questions