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February 28, 2015

February 28, 2015

Posted by **jamie** on Sunday, November 11, 2007 at 7:07pm.

2)an arrow is shot at 30.0 degree above the horizontal. it velocity is 49 m/s and it hits the target.

a)what is the maximum height the arrow will attain?

b)the target is at the height from which the arrow was shot. how far away is it?

somebody,please help. i don't understand these question

please help

- physic -
**bobpursley**, Sunday, November 11, 2007 at 7:27pmAll use the kinematic equations, which you should have memorized by now.

1) horizontal: 98=vcos45*t

solve for time in terms of v

th en put that time in the vertical equation

0=0+vsin45*t - 4.9t^2, and solve for v.

2) Same equations, start with vertical, solve for time, then in the horizontal, solve for distance.

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