Posted by Jon on Sunday, November 11, 2007 at 5:51pm.
Sorry, that's x times square root of ((x^2)+1)
f(x) = x(x^2 + 1)^(1/2)
f'(x) = (x)(1/2)(x^2+1)^(-1/2)(2x) + (1)(x^2+1)^(1/2)
f'(x) = (x^2)(x^2+1)^(-1/2) + (x^2+1)^(1/2)
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