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August 29, 2014

August 29, 2014

Posted by **Jon** on Sunday, November 11, 2007 at 5:51pm.

Please show work, and if you cannot display a graph in your answer, please provide the derivative asked in the first part of the question so I have a foundation to start with. Thanks in advance!

- Calculus -
**Jon**, Sunday, November 11, 2007 at 5:53pmSorry, that's x times square root of ((x^2)+1)

- Calculus -
**Raj**, Sunday, November 11, 2007 at 6:03pmf(x) = x(x^2 + 1)^(1/2)

f'(x) = (x)(1/2)(x^2+1)^(-1/2)(2x) + (1)(x^2+1)^(1/2)

f'(x) = (x^2)(x^2+1)^(-1/2) + (x^2+1)^(1/2)

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