The graph of a line through (2,3) that is perpendicular to the line with equation x = -1 also goes through which point?
How to work this????
Thanks.
perpendicular to the line with equation x = -1 means that your new line must be a horizontal line.
All horizontal lines have equation of the form y = c, where c is the y-coordinate of a point on that line.
So looking at our point (2,3) the equation must simply be
y = 3
The answers to choose from are (0,-1); (-2,3); (2,-4); or (1,4)
ok then
which of those points has y = 3 ????
To find the point through which the perpendicular line passes, we first need to know the slope of the line with equation x = -1.
The equation x = -1 represents a vertical line because the x-coordinate is fixed at -1, and the y-coordinate can take any value. Vertical lines have an undefined slope.
To find the slope of the line perpendicular to x = -1, we need to find the negative reciprocal of the slope of x = -1. Since the slope of x = -1 is undefined, the negative reciprocal is also undefined.
When a line has an undefined slope, it means it is a vertical line. For our case, the perpendicular line we are looking for must be a horizontal line.
A horizontal line is defined by the equation y = k, where k is a constant. Since the line needs to pass through the point (2,3), we can substitute these coordinates into the equation.
So, the equation of the line perpendicular to x = -1 and passing through (2,3) is y = 3.
Therefore, the point through which this line passes is (2,3).