Posted by **Michelle** on Sunday, November 11, 2007 at 1:39pm.

From the top of a 1900 m mountain, the angle of depression to a cathedral that is due east of the mountain is 38 degrees. The angle of depression to a bridge due north of the mountain is 42 degrees.

Find the straight-line distance from the cathedral to the bridge.

This is a question that needs visualizing as it has no diagram, but i know I have to draw a North/East/South/West grid.

- Gr. 12 Math - Trigonometry 3D -
**bobpursley**, Sunday, November 11, 2007 at 1:50pm
It is not possible to work without at least one dimensional measurement. The 1900 m on the mountain is not enough unless it somehow is relation to the elevation of the cathedral and the bridge.

- Gr. 12 Math - Trigonometry 3D -
**LOL**, Monday, February 25, 2008 at 2:48am
my bum bum

- Gr. 12 Math - Trigonometry 3D -
**Kris**, Sunday, June 15, 2008 at 2:35am
1 - find the dist. from the vertical base of the mountain to the cathedral and bridge via trig ratios (tan). remember that the angle of depression = looking horizontally ahead and taking the angle between your gaze and the target.

2 - use pythagoras to find the straight-line dist.

Note that you could not use this method if the cathedral and the bridge were not east-north of the base of the mountain.

The question could be formulated differently to make it more understandable. Instead of mountain, they could have put tower (or anything else that is completely vertical)

- Gr. 12 Math - Trigonometry 3D -
**Danielle**, Friday, December 19, 2008 at 3:25am
I would think that if you draw a line to represent the middle of the mounain and then draw a line 42 degrees to the right, then draw a nother line 38 degrees to the right. Because the height of the mountain is 1900 m, then you can just divide it by 100 to get 19 cm and then when you find where the line meets, times the amount back by 100 to get what measurement in m, the straight line is. I hope that helps. :D

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