Posted by Matthew on Saturday, November 10, 2007 at 7:19pm.
If f'=3, then f=3x+C, so f(8)]=24+C, but C=2 if f'=3. So f(8)=26
f(2)=8 by the same argument.
then if f'x=3, f(8)-f(2)=26-8=>18
You can make the same logic if f'=5, solve for C, then show that f(8)-f(2)<=30
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