Wednesday

October 1, 2014

October 1, 2014

Posted by **Anonymous** on Saturday, November 10, 2007 at 9:14am.

(tanx)(sinx) / (tanx) + (sinx) = (tanx) - (sinx) / (tanx)(sinx)

What I have so far:

L.S.

= (sinx / cosx) sinx / (sinx / cosx) + sinx

= (sin^2x / cosx) / (sinx + (sinx) (cosx) / cosx)

= (sin^2x / cosx) / (cosx / sinx + sinxcosx)

- Mathematics - Trigonometric Identities -
**Reiny**, Saturday, November 10, 2007 at 12:22pmyour equation is not an identity the way you wrote it,

try substituting any angle into the equation, it will not satisfy the equation.

The way you wrote it,

LS reduces to simply 2sinx

use brackets to identify the exact order of operation.

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